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Lambda Functions - Advanced Python 08
A lambda function is a small (one line) anonymous function that is defined without a name. A lambda function can take any number of arguments, but can only have one expression. While normal functions are defined using the def keyword, in Python anonymous functions are defined using the lambda keyword.
lambda arguments: expression
Lambda functions are used when a simple function is used only once or for a short period in your code. It's most common use is as an argument to higher-order functions (functions that takes in other functions as arguments). They are also used along with built-in functions like
# a lambda function that adds 10 to the input argument f = lambda x: x+10 val1 = f(5) val2 = f(100) print(val1, val2) # a lambda function that multiplies two input arguments and returns the result f = lambda x,y: x*y val3 = f(2,10) val4 = f(7,5) print(val3, val4)
15 110 20 35
Usage example: Lamdba inside another function
Return a customized lambda function from another function and create different function variations depending on your needs.
def myfunc(n): return lambda x: x * n doubler = myfunc(2) print(doubler(6)) tripler = myfunc(3) print(tripler(6))
Custom sorting using a lambda function as key parameter
The key function transforms each element before sorting.
points2D = [(1, 9), (4, 1), (5, -3), (10, 2)] sorted_by_y = sorted(points2D, key= lambda x: x) print(sorted_by_y) mylist = [- 1, -4, -2, -3, 1, 2, 3, 4] sorted_by_abs = sorted(mylist, key= lambda x: abs(x)) print(sorted_by_abs)
[(5, -3), (4, 1), (10, 2), (1, 9)] [-1, 1, -2, 2, -3, 3, -4, 4]
Use lambda for map function
map(func, seq), transforms each element with the function.
a = [1, 2, 3, 4, 5, 6] b = list(map(lambda x: x * 2 , a)) # However, try to prefer list comprehension # Use map if you have an already defined function c = [x*2 for x in a] print(b) print(c)
[2, 4, 6, 8, 10, 12] [2, 4, 6, 8, 10, 12]
Use lambda for filter function
filter(func, seq), returns all elements for which func evaluates to True.
a = [1, 2, 3, 4, 5, 6, 7, 8] b = list(filter(lambda x: (x%2 == 0) , a)) # However, the same can be achieved with list comprehension c = [x for x in a if x%2 == 0] print(b) print(c)
[2, 4, 6, 8] [2, 4, 6, 8]
reduce(func, seq), repeatedly applies the func to the elements and returns a single value.
func takes 2 arguments.
from functools import reduce a = [1, 2, 3, 4] product_a = reduce(lambda x, y: x*y, a) print(product_a) sum_a = reduce(lambda x, y: x+y, a) print(sum_a)
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